Return, as an array, the names of the model components
in the source expression of a dataset.
cpts = get_source_components();
cpts = get_source_components( dnum );
The routine is loaded into Sherpa with the call
require ("sherpa_utils");
The functions returns a String_Type array which contains the names
of the components used to define the source expression.
If no argument is given then dataset number 1 is
assumed, otherwise it uses the argument (dnum) as the
dataset number to use.
for dataset number 1.
This routine complements
get_source_expr() which returns the full source
expression.
sherpa> paramprompt off
sherpa> source = xsphabs[gal] * ( xsmekal[clus] + xspowerlaw[pl] )
sherpa> print( get_source_expr )
(gal * (clus + pl))
sherpa> cpts = get_source_components
sherpa> cpts
String_Type[3]
sherpa> print( cpts )
gal
clus
pl
Here we set up a source expression consisting of
a plasma model plus a powerlaw, both absorbed by the
"xsphabs" model.
The get_source_expr() routine returns a string listing
the full source expression, so we use the get_source_components()
routine from sherpa_utils.sl to break it down into its
compnenets (here "gal", "clus", and "pl").
Since we are using dataset number 1 then we do not
need to provide arguments to either the get_source_expr()
or get_source_components() routines. This means that
we can call these routines without the trailing "()".
sherpa> paramprompt off
sherpa> source 3 = xsphabs * ( xsmekal + xspowerlaw )
sherpa> print( get_source_expr(3) )
(xsphabs * (xsmekal + xspowerlaw))
sherpa> cpts = get_source_components(3)
sherpa> print( cpts )
xsphabs
xsmekal
xspowerlaw
This is very similar to the previous example except that
we are using dataset 3 - and so have to include it when calling
both get_source_expr() and get_source_components() - and
we do not provide our own names for the source components -
and so they default to the model names.
Please see "ahelp sherpa_utils" for information on
how to load these routines into Sherpa.
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